Files
ortools-clone/examples/contrib/DivisibleBy9Through1.java
2020-09-23 12:16:18 +02:00

185 lines
5.5 KiB
Java

// Copyright 2011 Hakan Kjellerstrand hakank@gmail.com
// Licensed under the Apache License, Version 2.0 (the "License");
// you may not use this file except in compliance with the License.
// You may obtain a copy of the License at
//
// http://www.apache.org/licenses/LICENSE-2.0
//
// Unless required by applicable law or agreed to in writing, software
// distributed under the License is distributed on an "AS IS" BASIS,
// WITHOUT WARRANTIES OR CONDITIONS OF ANY KIND, either express or implied.
// See the License for the specific language governing permissions and
// limitations under the License.
package com.google.ortools.contrib;
import com.google.ortools.Loader;
import com.google.ortools.constraintsolver.DecisionBuilder;
import com.google.ortools.constraintsolver.IntVar;
import com.google.ortools.constraintsolver.Solver;
import java.io.*;
import java.text.*;
import java.util.*;
public class DivisibleBy9Through1 {
/**
* A simple propagator for modulo constraint.
*
* <p>This implementation is based on the ECLiPSe version mentioned in "A Modulo propagator for
* ECLiPSE"
* http://www.hakank.org/constraint_programming_blog/2010/05/a_modulo_propagator_for_eclips.html
* The ECLiPSe Prolog source code: http://www.hakank.org/eclipse/modulo_propagator.ecl
*/
public static void my_mod(Solver solver, IntVar x, IntVar y, IntVar r) {
long lbx = x.min();
long ubx = x.max();
long ubx_neg = -ubx;
long lbx_neg = -lbx;
int min_x = (int) Math.min(lbx, ubx_neg);
int max_x = (int) Math.max(ubx, lbx_neg);
IntVar d = solver.makeIntVar(min_x, max_x, "d");
// r >= 0
solver.addConstraint(solver.makeGreaterOrEqual(r, 0));
// x*r >= 0
solver.addConstraint(solver.makeGreaterOrEqual(solver.makeProd(x, r).var(), 0));
// -abs(y) < r
solver.addConstraint(solver.makeLess(solver.makeOpposite(solver.makeAbs(y).var()).var(), r));
// r < abs(y)
solver.addConstraint(solver.makeLess(r, solver.makeAbs(y).var().var()));
// min_x <= d, i.e. d > min_x
solver.addConstraint(solver.makeGreater(d, min_x));
// d <= max_x
solver.addConstraint(solver.makeLessOrEqual(d, max_x));
// x == y*d+r
solver.addConstraint(
solver.makeEquality(x, solver.makeSum(solver.makeProd(y, d).var(), r).var()));
}
/**
* toNum(solver, a, num, base)
*
* <p>channelling between the array a and the number num
*/
private static void toNum(Solver solver, IntVar[] a, IntVar num, int base) {
int len = a.length;
IntVar[] tmp = new IntVar[len];
for (int i = 0; i < len; i++) {
tmp[i] = solver.makeProd(a[i], (int) Math.pow(base, (len - i - 1))).var();
}
solver.addConstraint(solver.makeEquality(solver.makeSum(tmp).var(), num));
}
/**
* Solves the divisible by 9 through 1 problem. See
* http://www.hakank.org/google_or_tools/divisible_by_9_through_1.py
*/
private static void solve(int base) {
Solver solver = new Solver("DivisibleBy9Through1");
//
// data
//
int m = (int) Math.pow(base, (base - 1)) - 1;
int n = base - 1;
String[] digits_str = {"_", "0", "1", "2", "3", "4", "5", "6", "7", "8", "9"};
System.out.println("base: " + base);
//
// variables
//
// digits
IntVar[] x = solver.makeIntVarArray(n, 1, base - 1, "x");
// the numbers. t[0] contains the answe
IntVar[] t = solver.makeIntVarArray(n, 0, m, "t");
//
// constraints
//
solver.addConstraint(solver.makeAllDifferent(x));
// Ensure the divisibility of base .. 1
IntVar zero = solver.makeIntConst(0);
for (int i = 0; i < n; i++) {
int mm = base - i - 1;
IntVar[] tt = new IntVar[mm];
for (int j = 0; j < mm; j++) {
tt[j] = x[j];
}
toNum(solver, tt, t[i], base);
IntVar mm_const = solver.makeIntConst(mm);
my_mod(solver, t[i], mm_const, zero);
}
//
// search
//
DecisionBuilder db = solver.makePhase(x, solver.INT_VAR_DEFAULT, solver.INT_VALUE_DEFAULT);
solver.newSearch(db);
//
// output
//
while (solver.nextSolution()) {
System.out.print("x: ");
for (int i = 0; i < n; i++) {
System.out.print(x[i].value() + " ");
}
System.out.println("\nt: ");
for (int i = 0; i < n; i++) {
System.out.print(t[i].value() + " ");
}
System.out.println();
if (base != 10) {
System.out.print("Number base 10: " + t[0].value());
System.out.print(" Base " + base + ": ");
for (int i = 0; i < n; i++) {
System.out.print(digits_str[(int) x[i].value() + 1]);
}
System.out.println("\n");
}
}
solver.endSearch();
// Statistics
System.out.println();
System.out.println("Solutions: " + solver.solutions());
System.out.println("Failures: " + solver.failures());
System.out.println("Branches: " + solver.branches());
System.out.println("Wall time: " + solver.wallTime() + "ms");
}
public static void main(String[] args) throws Exception {
Loader.loadNativeLibraries();
int base = 10;
if (args.length > 0) {
int new_base = Integer.parseInt(args[0]);
if (new_base > 10) {
// Note: The next valid base after 10 is 14 and
// the number 559922224824157, which is too large in this model.
System.out.println("Sorry, max allowed base is 10. Setting base to 10.");
} else if (new_base < 2) {
System.out.println("Sorry, min allowed base is 2. Setting base to 2.");
base = 2;
} else {
base = new_base;
}
}
DivisibleBy9Through1.solve(base);
}
}