- Fix examples using MPConstraint::Activity instead of MPSolver - Move all examples to exmaples/dotnet - remove netfx sub-directories - Add all examples to target test_dotnet - still few disabled since they are too long - Add tools/generate_examples_csproj.sh to generate .*proj files
242 lines
6.1 KiB
C#
242 lines
6.1 KiB
C#
//
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// Copyright 2012 Hakan Kjellerstrand
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//
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// Licensed under the Apache License, Version 2.0 (the "License");
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// you may not use this file except in compliance with the License.
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// You may obtain a copy of the License at
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//
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// http://www.apache.org/licenses/LICENSE-2.0
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//
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// Unless required by applicable law or agreed to in writing, software
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// distributed under the License is distributed on an "AS IS" BASIS,
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// WITHOUT WARRANTIES OR CONDITIONS OF ANY KIND, either express or implied.
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// See the License for the specific language governing permissions and
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// limitations under the License.
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using System;
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using System.Collections;
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using System.Collections.Generic;
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using System.Linq;
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using Google.OrTools.ConstraintSolver;
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public class KenKen2
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{
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/**
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* Ensure that the sum of the segments
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* in cc == res
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*
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*/
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public static void calc(Solver solver,
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int[] cc,
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IntVar[,] x,
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int res)
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{
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int ccLen = cc.Length;
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if (ccLen == 4) {
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// for two operands there's
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// a lot of possible variants
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IntVar a = x[cc[0]-1, cc[1]-1];
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IntVar b = x[cc[2]-1, cc[3]-1];
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IntVar r1 = a + b == res;
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IntVar r2 = a * b == res;
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IntVar r3 = a * res == b;
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IntVar r4 = b * res == a;
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IntVar r5 = a - b == res;
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IntVar r6 = b - a == res;
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solver.Add(r1+r2+r3+r4+r5+r6 >= 1);
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} else {
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// For length > 2 then res is either the sum
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// the the product of the segment
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// sum the numbers
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int len = cc.Length / 2;
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IntVar[] xx = (from i in Enumerable.Range(0, len)
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select x[cc[i*2]-1,cc[i*2+1]-1]).ToArray();
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// Sum
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IntVar this_sum = xx.Sum() == res;
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// Product
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// IntVar this_prod = (xx.Prod() == res).Var(); // don't work
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IntVar this_prod;
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if (xx.Length == 3) {
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this_prod = (x[cc[0]-1,cc[1]-1] *
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x[cc[2]-1,cc[3]-1] *
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x[cc[4]-1,cc[5]-1]) == res;
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} else {
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this_prod = (x[cc[0]-1,cc[1]-1] *
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x[cc[2]-1,cc[3]-1] *
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x[cc[4]-1,cc[5]-1] *
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x[cc[6]-1,cc[7]-1]) == res;
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}
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solver.Add(this_sum + this_prod >= 1);
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}
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}
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/**
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*
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* KenKen puzzle.
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*
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* http://en.wikipedia.org/wiki/KenKen
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* """
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* KenKen or KEN-KEN is a style of arithmetic and logical puzzle sharing
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* several characteristics with sudoku. The name comes from Japanese and
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* is translated as 'square wisdom' or 'cleverness squared'.
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* ...
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* The objective is to fill the grid in with the digits 1 through 6 such that:
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*
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* * Each row contains exactly one of each digit
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* * Each column contains exactly one of each digit
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* * Each bold-outlined group of cells is a cage containing digits which
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* achieve the specified result using the specified mathematical operation:
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* addition (+),
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* subtraction (-),
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* multiplication (x),
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* and division (/).
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* (Unlike in Killer sudoku, digits may repeat within a group.)
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*
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* ...
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* More complex KenKen problems are formed using the principles described
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* above but omitting the symbols +, -, x and /, thus leaving them as
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* yet another unknown to be determined.
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* """
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*
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* The solution is:
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*
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* 5 6 3 4 1 2
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* 6 1 4 5 2 3
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* 4 5 2 3 6 1
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* 3 4 1 2 5 6
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* 2 3 6 1 4 5
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* 1 2 5 6 3 4
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*
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*
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* Also see http://www.hakank.org/or-tools/kenken2.py
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* though this C# model has another representation of
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* the problem instance.
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*
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*/
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private static void Solve()
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{
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Solver solver = new Solver("KenKen2");
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// size of matrix
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int n = 6;
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IEnumerable<int> RANGE = Enumerable.Range(0, n);
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// For a better view of the problem, see
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// http://en.wikipedia.org/wiki/File:KenKenProblem.svg
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// hints
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// sum, the hints
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// Note: this is 1-based
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int[][] problem =
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{
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new int[] { 11, 1,1, 2,1},
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new int[] { 2, 1,2, 1,3},
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new int[] { 20, 1,4, 2,4},
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new int[] { 6, 1,5, 1,6, 2,6, 3,6},
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new int[] { 3, 2,2, 2,3},
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new int[] { 3, 2,5, 3,5},
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new int[] {240, 3,1, 3,2, 4,1, 4,2},
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new int[] { 6, 3,3, 3,4},
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new int[] { 6, 4,3, 5,3},
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new int[] { 7, 4,4, 5,4, 5,5},
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new int[] { 30, 4,5, 4,6},
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new int[] { 6, 5,1, 5,2},
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new int[] { 9, 5,6, 6,6},
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new int[] { 8, 6,1, 6,2, 6,3},
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new int[] { 2, 6,4, 6,5}
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};
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int num_p = problem.GetLength(0); // Number of segments
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//
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// Decision variables
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//
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IntVar[,] x = solver.MakeIntVarMatrix(n, n, 1, n, "x");
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IntVar[] x_flat = x.Flatten();
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//
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// Constraints
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//
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//
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// alldifferent rows and columns
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foreach(int i in RANGE) {
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// rows
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solver.Add( (from j in RANGE select x[i,j]).ToArray().AllDifferent());
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// cols
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solver.Add( (from j in RANGE select x[j,i]).ToArray().AllDifferent());
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}
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// Calculate the segments
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for(int i = 0; i < num_p; i++) {
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int[] segment = problem[i];
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// Remove the sum from the segment
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int len = segment.Length-1;
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int[] s2 = new int[len];
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Array.Copy(segment, 1, s2, 0, len);
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// sum this segment
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calc(solver, s2, x, segment[0]);
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}
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//
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// Search
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//
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DecisionBuilder db = solver.MakePhase(x_flat,
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Solver.INT_VAR_DEFAULT,
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Solver.INT_VALUE_DEFAULT);
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solver.NewSearch(db);
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while (solver.NextSolution()) {
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for(int i = 0; i < n; i++) {
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for(int j = 0; j < n; j++) {
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Console.Write(x[i,j].Value() + " ");
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}
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Console.WriteLine();
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}
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Console.WriteLine();
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}
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Console.WriteLine("\nSolutions: {0}", solver.Solutions());
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Console.WriteLine("WallTime: {0}ms", solver.WallTime());
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Console.WriteLine("Failures: {0}", solver.Failures());
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Console.WriteLine("Branches: {0} ", solver.Branches());
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solver.EndSearch();
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}
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public static void Main(String[] args)
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{
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Solve();
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}
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}
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