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ortools-clone/examples/notebook/contrib/crypta.ipynb
Corentin Le Molgat 27121a1068 Update examples/notebook
generated using ./tools/gen_all_notebook.sh
2020-03-04 14:34:33 +01:00

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{
"cells": [
{
"cell_type": "code",
"execution_count": null,
"metadata": {},
"outputs": [],
"source": [
"# Copyright 2010 Hakan Kjellerstrand hakank@gmail.com\n",
"#\n",
"# Licensed under the Apache License, Version 2.0 (the \"License\");\n",
"# you may not use this file except in compliance with the License.\n",
"# You may obtain a copy of the License at\n",
"#\n",
"# http://www.apache.org/licenses/LICENSE-2.0\n",
"#\n",
"# Unless required by applicable law or agreed to in writing, software\n",
"# distributed under the License is distributed on an \"AS IS\" BASIS,\n",
"# WITHOUT WARRANTIES OR CONDITIONS OF ANY KIND, either express or implied.\n",
"# See the License for the specific language governing permissions and\n",
"# limitations under the License.\n",
"\"\"\"\n",
"\n",
" Cryptarithmetic puzzle in Google CP Solver.\n",
"\n",
" Prolog benchmark problem GNU Prolog (crypta.pl)\n",
" '''\n",
" Name : crypta.pl\n",
" Title : crypt-arithmetic\n",
" Original Source: P. Van Hentenryck's book\n",
" Adapted by : Daniel Diaz - INRIA France\n",
" Date : September 1992\n",
"\n",
" Solve the operation:\n",
"\n",
" B A I J J A J I I A H F C F E B B J E A\n",
" + D H F G A B C D I D B I F F A G F E J E\n",
" -----------------------------------------\n",
" = G J E G A C D D H F A F J B F I H E E F\n",
" '''\n",
"\n",
"\n",
" Compare with the following models:\n",
" * Comet: http://hakank.org/comet/crypta.co\n",
" * MiniZinc: http://hakank.org/minizinc/crypta.mzn\n",
" * ECLiPSe: http://hakank.org/eclipse/crypta.ecl\n",
" * Gecode: http://hakank.org/gecode/crypta.cpp\n",
" * SICStus: http://hakank.org/sicstus/crypta.pl\n",
"\n",
" This model was created by Hakan Kjellerstrand (hakank@gmail.com)\n",
" Also see my other Google CP Solver models:\n",
" http://www.hakank.org/google_or_tools/\n",
"\"\"\"\n",
"from __future__ import print_function\n",
"from ortools.constraint_solver import pywrapcp\n",
"\n",
"\n",
"\n",
"# Create the solver.\n",
"solver = pywrapcp.Solver(\"Crypta\")\n",
"\n",
"#\n",
"# data\n",
"#\n",
"\n",
"#\n",
"# variables\n",
"#\n",
"LD = [solver.IntVar(0, 9, \"LD[%i]\" % i) for i in range(0, 10)]\n",
"A, B, C, D, E, F, G, H, I, J = LD\n",
"\n",
"Sr1 = solver.IntVar(0, 1, \"Sr1\")\n",
"Sr2 = solver.IntVar(0, 1, \"Sr2\")\n",
"\n",
"#\n",
"# constraints\n",
"#\n",
"solver.Add(solver.AllDifferent(LD))\n",
"solver.Add(B >= 1)\n",
"solver.Add(D >= 1)\n",
"solver.Add(G >= 1)\n",
"\n",
"solver.Add(A + 10 * E + 100 * J + 1000 * B + 10000 * B + 100000 * E +\n",
" 1000000 * F + E + 10 * J + 100 * E + 1000 * F + 10000 * G +\n",
" 100000 * A + 1000000 * F == F + 10 * E + 100 * E + 1000 * H +\n",
" 10000 * I + 100000 * F + 1000000 * B + 10000000 * Sr1)\n",
"\n",
"solver.Add(C + 10 * F + 100 * H + 1000 * A + 10000 * I + 100000 * I +\n",
" 1000000 * J + F + 10 * I + 100 * B + 1000 * D + 10000 * I +\n",
" 100000 * D + 1000000 * C + Sr1 == J + 10 * F + 100 * A + 1000 * F +\n",
" 10000 * H + 100000 * D + 1000000 * D + 10000000 * Sr2)\n",
"\n",
"solver.Add(A + 10 * J + 100 * J + 1000 * I + 10000 * A + 100000 * B + B +\n",
" 10 * A + 100 * G + 1000 * F + 10000 * H + 100000 * D + Sr2 == C +\n",
" 10 * A + 100 * G + 1000 * E + 10000 * J + 100000 * G)\n",
"\n",
"#\n",
"# search and result\n",
"#\n",
"db = solver.Phase(LD, solver.INT_VAR_SIMPLE, solver.INT_VALUE_SIMPLE)\n",
"\n",
"solver.NewSearch(db)\n",
"\n",
"num_solutions = 0\n",
"str = \"ABCDEFGHIJ\"\n",
"while solver.NextSolution():\n",
" num_solutions += 1\n",
" for (letter, val) in [(str[i], LD[i].Value()) for i in range(len(LD))]:\n",
" print(\"%s: %i\" % (letter, val))\n",
" print()\n",
"\n",
"solver.EndSearch()\n",
"\n",
"print()\n",
"print(\"num_solutions:\", num_solutions)\n",
"print(\"failures:\", solver.Failures())\n",
"print(\"branches:\", solver.Branches())\n",
"print(\"WallTime:\", solver.WallTime())\n",
"\n"
]
}
],
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"nbformat": 4,
"nbformat_minor": 4
}