183 lines
4.6 KiB
Python
183 lines
4.6 KiB
Python
# Copyright 2010 Hakan Kjellerstrand hakank@bonetmail.com
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#
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# Licensed under the Apache License, Version 2.0 (the "License");
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# you may not use this file except in compliance with the License.
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# You may obtain a copy of the License at
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#
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# http://www.apache.org/licenses/LICENSE-2.0
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#
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# Unless required by applicable law or agreed to in writing, software
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# distributed under the License is distributed on an "AS IS" BASIS,
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# WITHOUT WARRANTIES OR CONDITIONS OF ANY KIND, either express or implied.
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# See the License for the specific language governing permissions and
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# limitations under the License.
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"""
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Set partition problem in Google CP Solver.
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Problem formulation from
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http://www.koalog.com/resources/samples/PartitionProblem.java.html
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'''
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This is a partition problem.
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Given the set S = {1, 2, ..., n},
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it consists in finding two sets A and B such that:
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A U B = S,
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|A| = |B|,
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sum(A) = sum(B),
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sum_squares(A) = sum_squares(B)
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'''
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This model uses a binary matrix to represent the sets.
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Also, compare with other models which uses var sets:
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* MiniZinc: http://www.hakank.org/minizinc/set_partition.mzn
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* Gecode/R: http://www.hakank.org/gecode_r/set_partition.rb
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* Comet: http://hakank.org/comet/set_partition.co
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* Gecode: http://hakank.org/gecode/set_partition.cpp
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* ECLiPSe: http://hakank.org/eclipse/set_partition.ecl
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* SICStus: http://hakank.org/sicstus/set_partition.pl
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This model was created by Hakan Kjellerstrand (hakank@bonetmail.com)
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Also see my other Google CP Solver models: http://www.hakank.org/google_or_tools/
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"""
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import sys
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from constraint_solver import pywrapcp
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#
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# Partition the sets (binary matrix representation).
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#
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def partition_sets(x, num_sets, n):
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solver = x.values()[0].solver()
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for i in range(num_sets):
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for j in range(num_sets):
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if i != j:
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b = solver.Sum([x[i,k]*x[j,k] for k in range(n)])
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solver.Add(b == 0)
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# ensure that all integers is in
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# (exactly) one partition
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b = [x[i,j] for i in range(num_sets) for j in range(n) ]
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solver.Add(solver.Sum(b) == n)
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def main(n=16,num_sets=2):
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# Create the solver.
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solver = pywrapcp.Solver('Set partition')
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#
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# data
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#
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print "n:", n
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print "num_sets:", num_sets
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print
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# Check sizes
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assert n % num_sets == 0, "Equal sets is not possible."
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#
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# variables
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#
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# the set
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a = {}
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for i in range(num_sets):
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for j in range(n):
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a[i,j] = solver.IntVar(0, 1, 'a[%i,%i]' % (i,j))
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a_flat = [a[i,j] for i in range(num_sets) for j in range(n)]
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#
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# constraints
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#
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# partition set
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partition_sets(a, num_sets, n)
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for i in range(num_sets):
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for j in range(i, num_sets):
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# same cardinality
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solver.Add(solver.Sum([a[i,k] for k in range(n)])
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==
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solver.Sum([a[j,k] for k in range(n)]))
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# same sum
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solver.Add(solver.Sum([k*a[i,k] for k in range(n)])
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==
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solver.Sum([k*a[j,k] for k in range(n)]))
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# same sum squared
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solver.Add(solver.Sum([(k*a[i,k])*(k*a[i,k])
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for k in range(n)])
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==
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solver.Sum([(k*a[j,k])*(k*a[j,k])
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for k in range(n)]))
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# symmetry breaking for num_sets == 2
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if num_sets == 2:
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solver.Add(a[0,0] == 1)
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#
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# search and result
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#
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db = solver.Phase(a_flat,
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solver.INT_VAR_DEFAULT,
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solver.INT_VALUE_DEFAULT)
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solver.NewSearch(db)
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num_solutions = 0
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while solver.NextSolution():
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a_val = {}
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for i in range(num_sets):
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for j in range(n):
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a_val[i,j] = a[i,j].Value()
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sq = sum([(j+1)*a_val[0,j] for j in range(n)])
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print "sums:", sq
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sq2 = sum([((j+1)*a_val[0,j])**2 for j in range(n)])
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print "sums squared:", sq2
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for i in range(num_sets):
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if sum([a_val[i,j] for j in range(n)]):
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print i+1, ":",
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for j in range(n):
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if a_val[i,j] == 1:
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print j+1,
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print
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print
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num_solutions += 1
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solver.EndSearch()
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print
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print "num_solutions:", num_solutions
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print "failures:", solver.Failures()
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print "branches:", solver.Branches()
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print "WallTime:", solver.WallTime()
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n = 16
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num_sets = 2
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if __name__ == '__main__':
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if len(sys.argv) > 1:
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n = int(sys.argv[1])
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if len(sys.argv) > 2:
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num_sets = int(sys.argv[2])
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main(n, num_sets)
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