120 lines
3.2 KiB
Python
120 lines
3.2 KiB
Python
# Copyright 2010 Hakan Kjellerstrand hakank@bonetmail.com
|
|
#
|
|
# Licensed under the Apache License, Version 2.0 (the "License");
|
|
# you may not use this file except in compliance with the License.
|
|
# You may obtain a copy of the License at
|
|
#
|
|
# http://www.apache.org/licenses/LICENSE-2.0
|
|
#
|
|
# Unless required by applicable law or agreed to in writing, software
|
|
# distributed under the License is distributed on an "AS IS" BASIS,
|
|
# WITHOUT WARRANTIES OR CONDITIONS OF ANY KIND, either express or implied.
|
|
# See the License for the specific language governing permissions and
|
|
# limitations under the License.
|
|
|
|
"""
|
|
|
|
Cryptarithmetic puzzle in Google CP Solver.
|
|
|
|
Prolog benchmark problem GNU Prolog (crypta.pl)
|
|
'''
|
|
Name : crypta.pl
|
|
Title : crypt-arithmetic
|
|
Original Source: P. Van Hentenryck's book
|
|
Adapted by : Daniel Diaz - INRIA France
|
|
Date : September 1992
|
|
|
|
Solve the operation:
|
|
|
|
B A I J J A J I I A H F C F E B B J E A
|
|
+ D H F G A B C D I D B I F F A G F E J E
|
|
-----------------------------------------
|
|
= G J E G A C D D H F A F J B F I H E E F
|
|
'''
|
|
|
|
|
|
Compare with the following models:
|
|
* Comet: http://hakank.org/comet/crypta.co
|
|
* MiniZinc: http://hakank.org/minizinc/crypta.mzn
|
|
* ECLiPSe: http://hakank.org/eclipse/crypta.ecl
|
|
* Gecode: http://hakank.org/gecode/crypta.cpp
|
|
* SICStus: http://hakank.org/sicstus/crypta.pl
|
|
|
|
This model was created by Hakan Kjellerstrand (hakank@bonetmail.com)
|
|
Also see my other Google CP Solver models: http://www.hakank.org/google_or_tools/
|
|
"""
|
|
|
|
from constraint_solver import pywrapcp
|
|
|
|
|
|
def main():
|
|
|
|
# Create the solver.
|
|
solver = pywrapcp.Solver('Crypta')
|
|
|
|
#
|
|
# data
|
|
#
|
|
|
|
#
|
|
# variables
|
|
#
|
|
LD = [solver.IntVar(0, 9, 'LD[%i]' % i) for i in range(0,10)]
|
|
A,B,C,D,E,F,G,H,I,J = LD
|
|
|
|
Sr1 = solver.IntVar(0, 1, 'Sr1')
|
|
Sr2 = solver.IntVar(0, 1, 'Sr2')
|
|
|
|
#
|
|
# constraints
|
|
#
|
|
solver.Add(solver.AllDifferent(LD))
|
|
solver.Add(B >= 1)
|
|
solver.Add(D >= 1)
|
|
solver.Add(G >= 1)
|
|
|
|
solver.Add(A+10*E+100*J+1000*B+10000*B+100000*E+1000000*F+
|
|
E+10*J+100*E+1000*F+10000*G+100000*A+1000000*F
|
|
== F+10*E+100*E+1000*H+10000*I+100000*F+1000000*B+10000000*Sr1)
|
|
|
|
|
|
solver.Add(C+10*F+100*H+1000*A+10000*I+100000*I+1000000*J+
|
|
F+10*I+100*B+1000*D+10000*I+100000*D+1000000*C+Sr1
|
|
== J+10*F+100*A+1000*F+10000*H+100000*D+1000000*D+10000000*Sr2)
|
|
|
|
|
|
solver.Add(A+10*J+100*J+1000*I+10000*A+100000*B+
|
|
B+10*A+100*G+1000*F+10000*H+100000*D+Sr2
|
|
== C+10*A+100*G+1000*E+10000*J+100000*G)
|
|
|
|
|
|
#
|
|
# search and result
|
|
#
|
|
db = solver.Phase(LD,
|
|
solver.INT_VAR_SIMPLE,
|
|
solver.INT_VALUE_SIMPLE)
|
|
|
|
solver.NewSearch(db)
|
|
|
|
|
|
num_solutions = 0
|
|
str = "ABCDEFGHIJ"
|
|
while solver.NextSolution():
|
|
num_solutions += 1
|
|
for (letter, val) in [(str[i], LD[i].Value()) for i in range(len(LD))]:
|
|
print "%s: %i" % (letter, val)
|
|
print
|
|
|
|
solver.EndSearch()
|
|
|
|
print
|
|
print "num_solutions:", num_solutions
|
|
print "failures:", solver.failures()
|
|
print "branches:", solver.branches()
|
|
print "wall_time:", solver.wall_time()
|
|
|
|
|
|
if __name__ == '__main__':
|
|
main()
|