115 lines
3.3 KiB
Python
115 lines
3.3 KiB
Python
# Copyright 2010 Hakan Kjellerstrand hakank@gmail.com
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#
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# Licensed under the Apache License, Version 2.0 (the "License");
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# you may not use this file except in compliance with the License.
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# You may obtain a copy of the License at
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#
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# http://www.apache.org/licenses/LICENSE-2.0
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#
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# Unless required by applicable law or agreed to in writing, software
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# distributed under the License is distributed on an "AS IS" BASIS,
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# WITHOUT WARRANTIES OR CONDITIONS OF ANY KIND, either express or implied.
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# See the License for the specific language governing permissions and
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# limitations under the License.
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"""
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Cryptarithmetic puzzle in Google CP Solver.
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Prolog benchmark problem GNU Prolog (crypta.pl)
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'''
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Name : crypta.pl
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Title : crypt-arithmetic
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Original Source: P. Van Hentenryck's book
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Adapted by : Daniel Diaz - INRIA France
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Date : September 1992
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Solve the operation:
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B A I J J A J I I A H F C F E B B J E A
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+ D H F G A B C D I D B I F F A G F E J E
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-----------------------------------------
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= G J E G A C D D H F A F J B F I H E E F
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'''
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Compare with the following models:
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* Comet: http://hakank.org/comet/crypta.co
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* MiniZinc: http://hakank.org/minizinc/crypta.mzn
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* ECLiPSe: http://hakank.org/eclipse/crypta.ecl
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* Gecode: http://hakank.org/gecode/crypta.cpp
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* SICStus: http://hakank.org/sicstus/crypta.pl
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This model was created by Hakan Kjellerstrand (hakank@gmail.com)
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Also see my other Google CP Solver models:
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http://www.hakank.org/google_or_tools/
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"""
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from ortools.constraint_solver import pywrapcp
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def main():
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# Create the solver.
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solver = pywrapcp.Solver("Crypta")
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#
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# data
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#
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#
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# variables
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#
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LD = [solver.IntVar(0, 9, "LD[%i]" % i) for i in range(0, 10)]
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A, B, C, D, E, F, G, H, I, J = LD
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Sr1 = solver.IntVar(0, 1, "Sr1")
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Sr2 = solver.IntVar(0, 1, "Sr2")
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#
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# constraints
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#
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solver.Add(solver.AllDifferent(LD))
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solver.Add(B >= 1)
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solver.Add(D >= 1)
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solver.Add(G >= 1)
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solver.Add(A + 10 * E + 100 * J + 1000 * B + 10000 * B + 100000 * E +
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1000000 * F + E + 10 * J + 100 * E + 1000 * F + 10000 * G +
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100000 * A + 1000000 * F == F + 10 * E + 100 * E + 1000 * H +
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10000 * I + 100000 * F + 1000000 * B + 10000000 * Sr1)
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solver.Add(C + 10 * F + 100 * H + 1000 * A + 10000 * I + 100000 * I +
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1000000 * J + F + 10 * I + 100 * B + 1000 * D + 10000 * I +
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100000 * D + 1000000 * C + Sr1 == J + 10 * F + 100 * A + 1000 * F +
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10000 * H + 100000 * D + 1000000 * D + 10000000 * Sr2)
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solver.Add(A + 10 * J + 100 * J + 1000 * I + 10000 * A + 100000 * B + B +
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10 * A + 100 * G + 1000 * F + 10000 * H + 100000 * D + Sr2 == C +
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10 * A + 100 * G + 1000 * E + 10000 * J + 100000 * G)
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#
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# search and result
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#
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db = solver.Phase(LD, solver.INT_VAR_SIMPLE, solver.INT_VALUE_SIMPLE)
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solver.NewSearch(db)
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num_solutions = 0
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str = "ABCDEFGHIJ"
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while solver.NextSolution():
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num_solutions += 1
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for (letter, val) in [(str[i], LD[i].Value()) for i in range(len(LD))]:
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print("%s: %i" % (letter, val))
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print()
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solver.EndSearch()
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print()
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print("num_solutions:", num_solutions)
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print("failures:", solver.Failures())
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print("branches:", solver.Branches())
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print("WallTime:", solver.WallTime())
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if __name__ == "__main__":
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main()
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