OR-Tools  9.3
cutting_stock.cc
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1// Copyright 2010-2021 Google LLC
2// Licensed under the Apache License, Version 2.0 (the "License");
3// you may not use this file except in compliance with the License.
4// You may obtain a copy of the License at
5//
6// http://www.apache.org/licenses/LICENSE-2.0
7//
8// Unless required by applicable law or agreed to in writing, software
9// distributed under the License is distributed on an "AS IS" BASIS,
10// WITHOUT WARRANTIES OR CONDITIONS OF ANY KIND, either express or implied.
11// See the License for the specific language governing permissions and
12// limitations under the License.
13
14// The Cutting Stock problem is as follows. You begin with unlimited boards, all
15// of the same length. You are also given a list of smaller pieces to cut out,
16// each with a length and a demanded quantity. You want to cut out all these
17// pieces using as few of your starting boards as possible.
18//
19// E.g. you begin with boards that are 20 feet long, and you must cut out 3
20// pieces that are 6 feet long and 5 pieces that are 8 feet long. An optimal
21// solution is:
22// [(6,), (8, 8) (8, 8), (6, 6, 8)]
23// (We cut a 6 foot piece from the first board, two 8 foot pieces from
24// the second board, and so on.)
25//
26// This example approximately solves the problem with a column generation
27// heuristic. The leader problem is a set cover problem, and the worker is a
28// knapsack problem. We alternate between solving the LP relaxation of the
29// leader incrementally, and solving the worker to generate new a configuration
30// (a column) for the leader. When the worker can no longer find a column
31// improving the LP cost, we convert the leader problem to a MIP and solve
32// again. We now give precise statements of the leader and worker.
33//
34// Problem data:
35// * l_i: the length of each piece we need to cut out.
36// * d_i: how many copies each piece we need.
37// * L: the length of our initial boards.
38// * q_ci: for configuration c, the quantity of piece i produced.
39//
40// Leader problem variables:
41// * x_c: how many copies of configuration c to produce.
42//
43// Leader problem formulation:
44// min sum_c x_c
45// s.t. sum_c q_ci * x_c = d_i for all i
46// x_c >= 0, integer for all c.
47//
48// The worker problem is to generate new configurations for the leader problem
49// based on the dual variables of the demand constraints in the LP relaxation.
50// Worker problem data:
51// * p_i: The "price" of piece i (dual value from leader's demand constraint)
52//
53// Worker decision variables:
54// * y_i: How many copies of piece i should be in the configuration.
55//
56// Worker formulation
57// max sum_i p_i * y_i
58// s.t. sum_i l_i * y_i <= L
59// y_i >= 0, integer for all i
60//
61// An optimal solution y* defines a new configuration c with q_ci = y_i* for all
62// i. If the solution has objective value <= 1, no further improvement on the LP
63// is possible. For additional background and proofs see:
64// https://people.orie.cornell.edu/shmoys/or630/notes-06/lec16.pdf
65// or any other reference on the "Cutting Stock Problem".
66//
67// Note: this problem is equivalent to symmetric bin packing:
68// https://en.wikipedia.org/wiki/Bin_packing_problem#Formal_statement
69// but typically in bin packing it is not assumed that you should exploit having
70// multiple items of the same size.
71#include <iostream>
72#include <limits>
73#include <utility>
74#include <vector>
75
76#include "absl/status/status.h"
77#include "absl/status/statusor.h"
83
84namespace {
85
87constexpr double kInf = std::numeric_limits<double>::infinity();
88
89// piece_sizes and piece_demands must have equal length.
90// every piece must have 0 < size <= board_length.
91// every piece must have demand > 0.
92struct CuttingStockInstance {
93 std::vector<int> piece_sizes;
94 std::vector<int> piece_demands;
95 int board_length;
96};
97
98// pieces and quantity must have equal size.
99// Defined for a related CuttingStockInstance, the total length all pieces
100// weighted by their quantity must not exceed board_length.
101struct Configuration {
102 std::vector<int> pieces;
103 std::vector<int> quantity;
104};
105
106// configurations and quantity must have equal size.
107// objective_value is the sum of the vales in quantity (how many total boards
108// are used).
109// To be feasible, the demand for each piece type must be met by the produced
110// configurations.
111struct CuttingStockSolution {
112 std::vector<Configuration> configurations;
113 std::vector<int> quantity;
114 int objective_value = 0;
115};
116
117// Solves the worker problem.
118//
119// Solves the problem on finding the configuration (with its objective value) to
120// add the to model that will give the greatest improvement in the LP
121// relaxation. This is equivalent to a knapsack problem.
122absl::StatusOr<std::pair<Configuration, double>> BestConfiguration(
123 const std::vector<double>& piece_prices,
124 const std::vector<int>& piece_sizes, const int board_size) {
125 int num_pieces = piece_prices.size();
126 CHECK_EQ(piece_sizes.size(), num_pieces);
127 math_opt::Model model("knapsack");
128 std::vector<math_opt::Variable> pieces;
129 for (int i = 0; i < num_pieces; ++i) {
130 pieces.push_back(
131 model.AddIntegerVariable(0, kInf, absl::StrCat("item_", i)));
132 }
133 model.Maximize(math_opt::InnerProduct(pieces, piece_prices));
134 model.AddLinearConstraint(math_opt::InnerProduct(pieces, piece_sizes) <=
135 board_size);
136 ASSIGN_OR_RETURN(const math_opt::SolveResult solve_result,
137 math_opt::Solve(model, math_opt::SolverType::kCpSat));
138 if (solve_result.termination.reason !=
139 math_opt::TerminationReason::kOptimal) {
141 << "Failed to solve knapsack pricing problem to optimality: "
142 << solve_result.termination;
143 }
144 Configuration config;
145 for (int i = 0; i < num_pieces; ++i) {
146 const int use = static_cast<int>(
147 std::round(solve_result.variable_values().at(pieces[i])));
148 if (use > 0) {
149 config.pieces.push_back(i);
150 config.quantity.push_back(use);
151 }
152 }
153 return std::make_pair(config, solve_result.objective_value());
154}
155
156// Solves the full cutting stock problem by decomposition.
157absl::StatusOr<CuttingStockSolution> SolveCuttingStock(
158 const CuttingStockInstance& instance) {
159 math_opt::Model model("cutting_stock");
160 model.set_minimize();
161 const int n = instance.piece_sizes.size();
162 std::vector<math_opt::LinearConstraint> demand_met;
163 for (int i = 0; i < n; ++i) {
164 const int d = instance.piece_demands[i];
165 demand_met.push_back(model.AddLinearConstraint(d, d));
166 }
167 std::vector<std::pair<Configuration, math_opt::Variable>> configs;
168 auto add_config = [&](const Configuration& config) {
169 const math_opt::Variable v = model.AddContinuousVariable(0.0, kInf);
170 model.set_objective_coefficient(v, 1);
171 for (int i = 0; i < config.pieces.size(); ++i) {
172 const int item = config.pieces[i];
173 const int use = config.quantity[i];
174 if (use >= 1) {
175 model.set_coefficient(demand_met[item], v, use);
176 }
177 }
178 configs.push_back({config, v});
179 };
180
181 // To ensure the leader problem is always feasible, begin a configuration for
182 // every item that has a single copy of the item.
183 for (int i = 0; i < n; ++i) {
184 add_config(Configuration{.pieces = {i}, .quantity = {1}});
185 }
186
188 &model, math_opt::SolverType::kGlop));
189 int pricing_round = 0;
190 while (true) {
191 ASSIGN_OR_RETURN(math_opt::SolveResult solve_result, solver->Solve());
192 if (solve_result.termination.reason !=
193 math_opt::TerminationReason::kOptimal) {
195 << "Failed to solve leader LP problem to optimality at "
196 "iteration "
197 << pricing_round << " termination: " << solve_result.termination;
198 }
199 if (!solve_result.has_dual_feasible_solution()) {
200 // MathOpt does not require solvers to return a dual solution on optimal,
201 // but most LP solvers always will, see go/mathopt-solver-contracts for
202 // details.
204 << "no dual solution was returned with optimal solution at "
205 "iteration "
206 << pricing_round;
207 }
208 std::vector<double> prices;
209 for (const math_opt::LinearConstraint d : demand_met) {
210 prices.push_back(solve_result.dual_values().at(d));
211 }
213 (const auto [config, value]),
214 BestConfiguration(prices, instance.piece_sizes, instance.board_length));
215 if (value <= 1 + 1e-3) {
216 // The LP relaxation is solved, we can stop adding columns.
217 break;
218 }
219 add_config(config);
220 LOG(INFO) << "round: " << pricing_round
221 << " lp objective: " << solve_result.objective_value();
222 pricing_round++;
223 }
224 LOG(INFO) << "Done adding columns, switching to MIP";
225 for (const auto& [config, var] : configs) {
226 model.set_integer(var);
227 }
228 ASSIGN_OR_RETURN(const math_opt::SolveResult solve_result,
229 math_opt::Solve(model, math_opt::SolverType::kCpSat));
230 switch (solve_result.termination.reason) {
231 case math_opt::TerminationReason::kOptimal:
232 case math_opt::TerminationReason::kFeasible:
233 break;
234 default:
236 << "Failed to solve final cutting stock MIP, termination: "
237 << solve_result.termination;
238 }
239 CuttingStockSolution solution;
240 for (const auto& [config, var] : configs) {
241 int use =
242 static_cast<int>(std::round(solve_result.variable_values().at(var)));
243 if (use > 0) {
244 solution.configurations.push_back(config);
245 solution.quantity.push_back(use);
246 solution.objective_value += use;
247 }
248 }
249 return solution;
250}
251
252absl::Status RealMain() {
253 // Data from https://en.wikipedia.org/wiki/Cutting_stock_problem
254 CuttingStockInstance instance;
255 instance.board_length = 5600;
256 instance.piece_sizes = {1380, 1520, 1560, 1710, 1820, 1880, 1930,
257 2000, 2050, 2100, 2140, 2150, 2200};
258 instance.piece_demands = {22, 25, 12, 14, 18, 18, 20, 10, 12, 14, 16, 18, 20};
259 ASSIGN_OR_RETURN(CuttingStockSolution solution, SolveCuttingStock(instance));
260 std::cout << "Best known solution uses 73 rolls." << std::endl;
261 std::cout << "Total rolls used in actual solution found: "
262 << solution.objective_value << std::endl;
263 return absl::OkStatus();
264}
265
266} // namespace
267
268int main(int argc, char** argv) {
269 InitGoogle(argv[0], &argc, &argv, true);
270 absl::Status result = RealMain();
271 if (!result.ok()) {
272 std::cout << result;
273 return 1;
274 }
275 return 0;
276}
#define CHECK_EQ(val1, val2)
Definition: base/logging.h:703
#define LOG(severity)
Definition: base/logging.h:420
#define ASSIGN_OR_RETURN(lhs, rexpr)
static absl::StatusOr< std::unique_ptr< IncrementalSolver > > New(Model *model, SolverType solver_type, SolverInitArguments arguments={})
Definition: solve.cc:104
int main(int argc, char **argv)
int64_t value
IntVar * var
Definition: expr_array.cc:1874
GRBmodel * model
void InitGoogle(const char *usage, int *argc, char ***argv, bool deprecated)
Definition: init_google.h:32
const int INFO
Definition: log_severity.h:31
absl::StatusOr< SolveResult > Solve(const Model &model, const SolverType solver_type, const SolveArguments &solve_args, const SolverInitArguments &init_args)
Definition: solve.cc:94
LinearExpression InnerProduct(const LeftIterable &left, const RightIterable &right)
StatusBuilder InternalErrorBuilder()
const LinearConstraintMap< double > & dual_values() const
const VariableMap< double > & variable_values() const
double objective_value